Corrigé des exercices.

LES EXPOSANTS ET LES PARENTHÈSES - Exercices - Corrigé 1. Compléter le tableau suivant : |Puissance |Base |Exposant |Notation développée |
| |2 |3 |( 2 ) x ( 2 ) x ( 2 ) |
|23 | | | |
| |8 |3 |8 x 8 x 8 |
|83 | | | |
| |-4 |5 |(-4) x (-4) x (-4) x |
|(-4)5 | | |(-4) x (-4) |
| |-6 |3 |-6 x -6 x -6 |
|(-6)3 | | | |
| |-3 |4 |(-1) x (-3) x (-3) x |
|-(-3)4 | | |(-3) x (-3) |
| |-9 |2 |(-9) x (-9) |
|(-9)2 | | | |
| |5 |3 |(-1) x 5 x 5 x 5 |
|-53 | | | |
| |-3 |4 |(-3) x (-3) x (-3) x |
|(-3)4 | | |(-3) |
| |-2 |5 |(-2) x (-2) x (-2) x |
|(-2)5 | | |(-2) x (-2) |
| |3 |4 |(-1) x (3) x (3) x (3)|
|-(3)4 | | |x (3) |
| |-2 |3 |- (-2) x (-2) x (-2) |
|-(-2)3 | | | |
| |-7 |4 |(-7) x (-7) x (-7) x |
|(-7)4 | | |(-7) | 2. Exprimer ces puissances en notation développée et en déterminer la
valeur. a. 52 = 5 x 5 x 5 = 125
b. -43 = ( -1 ) x 4 x 4 x 4 = - 64
c. (-25) = ( -2 ) x ( -2 ) x ( -2 ) x ( -2 ) x ( -2 ) = - 32
d. (-3)4 = ( -3 ) x ( -3 ) x ( -3 ) x ( -3 ) = 81
e. 53 = 5 x 5 x 5 = 125
f. -63 = ( -1 ) x 6 x 6 x 6 = - 216
g. (-52) = ( -1 ) x 5 x 5 = - 25
h. (-7)3 = ( -7 ) x ( -7 ) x ( -7 ) = - 243