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Exercice :

Exercice : 2003/2004 ... M(C8H10N4O2) = 8x12+10+4x14+2x16 = 194 g.mol-1; P
(C) = 8x100/24 ... 3. n(caffeine) = m/M A.N. : n = 80.10-3 / 194 = 4,1.10-4 mol. 4.

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