Corrigé du fascicule d'exercices pour les UE de Maths 2 et Maths ...
2)4k(?1)2k cos. (2k?. 2. ) x4k. (4k)!. = +?. ? k=0. (?1)k22k?2 x4k. (4k)! . ?x ? R, cosxchx = ?+? k=0. (?1)k22k?2 x4k. (4k)! . Correction de l' ...
2)4k(?1)2k cos. (2k?. 2. ) x4k. (4k)!. = +?. ? k=0. (?1)k22k?2 x4k. (4k)! . ?x ? R, cosxchx = ?+? k=0. (?1)k22k?2 x4k. (4k)! . Correction de l' ...