Corrigé du baccalauréat S Asie 18 juin 2019 - APMEP
?P ??P = -?G1/?V car ?G2= 0. 1atm = 1,013.105 Pascal. Joule = 1Pa.m3= 1,013.105atm .m3. ?v = var ? vcal = -2,75cm3.mol- ...
?P ??P = -?G1/?V car ?G2= 0. 1atm = 1,013.105 Pascal. Joule = 1Pa.m3= 1,013.105atm .m3. ?v = var ? vcal = -2,75cm3.mol- ...